The goal of this post is to describe a new stratification of Rann(M)×R⩾0 that builds on the ideas from a previous post (see "The point-counting stratification of the Ran space is conical (really though) ," 2017-11-15) and some newer ones.
Let SCn be the set of simplicial complexes on n ordered vertices. There is a natural partial order on SCn given by inclusion of sets, viewing every simplex as a subset of the power set P({1,…,n}). The symmetric group Sn has a natural action on SCn and SCn/Sn has an induced partial order as well. Hence we have a map
f : Rann(M)×R⩾0→SCn/Sn,(P,t)↦VR(P,t),
where VR(P,t) is the Vietoris-Rips complex on P with radius t. We include a k-cell in VR(P,t) at the vertices {P0,…,Pk}⊂P if d(Pi,Pj)<t for all 0⩽i<j⩽k. Because we have strict inequality, the map is continuous in the upwards-directed, or Alexandrov topology on SCn/Sn. Indeed, taking the preimage of an open set US in SCn/Sn based at some simplicial complex S (such US form the basis of topology on SCn/Sn), there is an open ball of radius mini<jd(Pi,Pj)/2 in the Rann(M) component and min(Pi,Pj)⊂f(P,t)|t−d(Pi,Pj)| in the R⩾0 component around any (P,t)∈f−1(US).
Remark: The above shows that Rann(M)×R⩾0 is poset-stratified by SCn/Sn, in the sense of Definition A.5.1 of Lurie. However, the strata are all of the same dimension, so there is no chance of this being a conical stratification, in the sense of Definition A.5.5 of Lurie. We hope to fix that with a different stratification.
Definition: Construct a poset (A,⩽A) in the following way:
g : Rann(M)×R⩾0→A,(P,t)↦{S, if (P,t)∈int(f−1(S)) for some S∈SCn/Sn,aS1⋯Sk, if (P,t)∈cl(f−1(T)) ⟺ T∈{S1,…,Sk}.
We now claim that g is a stratifying map.
Proposition: The map g is continuous.
Proof: Since int(f−1(S))∩int(f−1(T))=∅ for all S≠T∈SCn/Sn, the open sets US⊆A based at S all have open preimage g−1(US)⊆X. Now take (P,t)∈g−1(UaS1⋯Sk), for k⩾2. If every open ball around (P,t)∈X intersects XaT, for some T⊆SCn/Sn, then (P,t) must be in the closure of f−1(T), for every T∈T. Hence the only possible such T are T⊆{S1,…,Sk}, so g−1(UaS1⋯Sk) is open in X. ◻
The next step would be to show that this stratification is conical, though it is not clear yet if it is.
References: Lurie (Higher Algebra, Appendix A)
Let SCn be the set of simplicial complexes on n ordered vertices. There is a natural partial order on SCn given by inclusion of sets, viewing every simplex as a subset of the power set P({1,…,n}). The symmetric group Sn has a natural action on SCn and SCn/Sn has an induced partial order as well. Hence we have a map
f : Rann(M)×R⩾0→SCn/Sn,(P,t)↦VR(P,t),
where VR(P,t) is the Vietoris-Rips complex on P with radius t. We include a k-cell in VR(P,t) at the vertices {P0,…,Pk}⊂P if d(Pi,Pj)<t for all 0⩽i<j⩽k. Because we have strict inequality, the map is continuous in the upwards-directed, or Alexandrov topology on SCn/Sn. Indeed, taking the preimage of an open set US in SCn/Sn based at some simplicial complex S (such US form the basis of topology on SCn/Sn), there is an open ball of radius mini<jd(Pi,Pj)/2 in the Rann(M) component and min(Pi,Pj)⊂f(P,t)|t−d(Pi,Pj)| in the R⩾0 component around any (P,t)∈f−1(US).
Remark: The above shows that Rann(M)×R⩾0 is poset-stratified by SCn/Sn, in the sense of Definition A.5.1 of Lurie. However, the strata are all of the same dimension, so there is no chance of this being a conical stratification, in the sense of Definition A.5.5 of Lurie. We hope to fix that with a different stratification.
Definition: Construct a poset (A,⩽A) in the following way:
- SCn/Sn⊂A, with S⩽AT whenever S⩽SCn/SnT ,
- for every S≠T∈SCn/Sn, let aST∈A with aST⩽AS and aST⩽AT,
- for every {S1,…,Sk>2}⊂SCn/Sn, let aS1⋯Sk∈A with aS1⋯Sk⩽AaS1⋯^Si⋯Sk for all 1⩽i⩽k.
g : Rann(M)×R⩾0→A,(P,t)↦{S, if (P,t)∈int(f−1(S)) for some S∈SCn/Sn,aS1⋯Sk, if (P,t)∈cl(f−1(T)) ⟺ T∈{S1,…,Sk}.
We now claim that g is a stratifying map.
Proposition: The map g is continuous.
Proof: Since int(f−1(S))∩int(f−1(T))=∅ for all S≠T∈SCn/Sn, the open sets US⊆A based at S all have open preimage g−1(US)⊆X. Now take (P,t)∈g−1(UaS1⋯Sk), for k⩾2. If every open ball around (P,t)∈X intersects XaT, for some T⊆SCn/Sn, then (P,t) must be in the closure of f−1(T), for every T∈T. Hence the only possible such T are T⊆{S1,…,Sk}, so g−1(UaS1⋯Sk) is open in X. ◻
The next step would be to show that this stratification is conical, though it is not clear yet if it is.
References: Lurie (Higher Algebra, Appendix A)
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