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Thursday, August 25, 2016

Equations on Riemann surfaces

Recall that a Riemann surface is a complex 1-manifold M with a complex structure Σ (a class of analytically equivalent atlases on X). Here we consider equations that relate connections and Higgs fields with solutions on Riemann surfaces. Let G=SU(2) (complex 2-matrices with determinant 1) or SO(3) (real orthogonal 3-matrices with determinant 1), θ a Higgs field over M, and  P a principal G-bundle over M.

Definition:
The curvature of a principal G-bundle P is the map
F : A0M(P)A2M(P),ωs(d)(ωs),
where the extension d:AkM(P)Ak+1M(P) is defined by the Leibniz rule, that is d(ωs)=(dω)s+(1)kωs, for ω a k-form and s a smooth section of P.

Since we may write A1=A1,0A0,1 as the sum of its holomorphic and anti-holomorphic parts, respectively (see post "Smooth projective varieties as Kähler manifolds," 2016-06-16), we may consider the restriction of d to either of these summands.

Definition: For a vector space V, define the Hodge star by
 : k(V)nk(V),ei1eikej1ejnk,
so that ei1eikej1ejnk=e1en. Extend by linearity from the chosen basis.

The dual of the generalized connection d is written d=(1)m+mk+1d, where dim(M)=m and the argument of d is in AkM (this holds for manifolds M that are not necessarily Riemann surfaces as well).

Now we may understand some equations on Riemann surfaces. They all deal with the connection , its generalization d, its curvature F, and the Higgs field θ. Below we indicate their names and where they are mentioned (and described in further detail).
Hitchin equationsd|A0,1θ=0[2], IntroductionF+[θ,θ]=0Yang-Mills equationsddθ+[F,θ]=0[1], Section 4dθ=0self-dual Yang-Mills equationFF=0[2], Section 1Yang-Mills-Higgs equationsdF+[θ,dθ]=0[4], equation (1)ddθ=0

Recall the definitions of θ and θ from a previous post ("Higgs fields of principal bundles," 2016-08-24). Now we look at these equations in more detail. The first of the Hitchin equations says that θ has no anti-holomorphic component, or in other words, that θ is holomorphic. In the second equation, the Lie bracket [,] of the two 1-forms is
[θ,θ]=[12f(dz+i dy),12ˉf(dzi dy)]=i4fˉf dxdy+i4fˉf dydxi4fˉf dxdy+i4fˉf dydx=i|f|2 dxdy.
In the Yang-Mills and Yang-Mills-Higgs equations, we can simplify some parts by noting that, for a section s of the complexification of P×adg,
d(θs)=12d(fdxs)+i2d(fdys)=12(dfdxsfdxs)+i2(dfdyfdys)=(i2fx12fy)dxdys12f(dx+idy)θs.
The Hodge star of θ is θ=12f(dyidx), so
d(θs)=12d(fdys)i2d(fdxs)=12(dfdysfdys)i2(dfdxfdxs)=(12fx+i2fy)dxdys+12f(idxdy)iθs.
We could express s=(s1dx+s2dy)s1, but that would not be too enlightening. Next, note the self-dual Yang-Mills equation only makes sense over a (real) 4-dimensional space, since the degrees of the forms have to match up. In that case, with a basis dz1=dx1+idy1,dz2=dx2+idy2 of A1, we have
F=F12dx1dy1+F13dx1dx2+F14dx1dy2+F23dy1dx2+F24dy1dy2+F34dx2dy2,F=F12dx2dy2F13dy1dy2+F14dy1dx2+F23dx1dy2F24dx1dx2+F34dx1dy1.
Then the self-dual equation simply claims that
F12=F34,F13=F24,F14=F23.

Remark:
This title of this post promises to talk about equations on Riemann surfaces, yet all the differential forms are valued in a principal G-bundle over R2 (or R4). However, since the given equations are conformally invariant (this is not obvious), and as a Riemann surface locally looks like R2, we may consider the solutions to the equations as living on a Riemann surface.

References:
[1] Atiyah and Bott (The Yang-Mills equations over Riemann surfaces)
[2] Hitchin (Self-duality equations on a Riemann surface)
[3] Huybrechts (Complex Geometry, Chapter 4.3)
[4] Taubes (On the Yang-Mills-Higgs equations)

Wednesday, August 24, 2016

Higgs fields of principal bundles

The goal here is to understand the setting of Higgs fields on Riemannian manifolds, in the manner of Hitchin. First we consider general topological spaces X and groups G.

Definition: Let X be a topological space and G a group. A principal bundle (or principal G-bundle) P over X is a fiber bundle π:PX together with a continuous, free, and transitive right action P×GP that preserves the fibers. That is, if pπ1(x), then pgπ1(x) for all gG and xX.

Now suppose we have a principal bundle π:PX, a representation ρ of G, and another space Y on which G acts on the left. Define an equivalence relation (p,y)(p,y) on P×Y iff there is some gG for which p=pg and y=ρ(g1)y. This is an equivalence relation. We will be interested in the adjoint representation (induced by conjugation).

Proposition: The projection map π:P×ρY:=(P×Y)/ X, where π([p,y])=π(p), defines a vector bundle over X, called the associated bundle of P.

Recall a Lie group G is a group that is also a topological space, in the sense that there is a continuous map G×GG, given by (g,h)gh1. The Lie algebra g of the Lie group G is the tangent space TeG of G at the identity e. We will be interested in principal G-bundles PR2 and associated bundles P×adgR2, where ad is the adjoint representation of G.

Next, recall we had the space AkM of k-differential forms on M (see post "Smooth projective varieties as Kähler manifiolds," 2016-06-16), defined in terms of wedge products of elements in the cotangent bundle (TM)=TM of M. Now we generalize this to get differential forms over arbitrary vector bundles.

Definition: Let EM be a vector bundle. Let
AkM(E):=Γ(EkTM)=Γ(E)A0MAkM,Ap,qM(E):=Γ(Ep(T1,0M)q(T0,1M))=Γ(E)A0MAp,qM
be the spaces of k- and (p,q)-differential forms, respectively, over M with values in E.

Equality above follows by functoriality. Now we are close to understanding where exactly the Higgs field lives, in Hitchin's context.

Definition: Given a function f:CC, the conjugate of f is ˉf, defined by ˉf(z)=¯f(ˉz).

Hitchin denotes this as f, but we will stick to ˉf. Finally, let P be a G-principal bundle over R2 and P×adg the associated bundle of P. Given fA0R2((P×adg)C), set
θ=12f(dx+i dy)A1,0R2((P×adg)C),θ=12ˉf(dxi dy)A0,1R2((P×adg)C),
called a Higgs field over R2 and (presumably) a dual (or conjugate) Higgs field over R2. Note this agrees with the definition in a previous post ("Connections, curvature, and Higgs bundles," 2016-07-25).

References: Hitchin (Self-duality equations on a Riemann surface), Wikipedia (article on associated bundles, article on vector-valued differential forms)

Saturday, August 13, 2016

What is a stack?

 Conference topic

This is from discussions at the 2016 West Coast Algebraic Topology Summer School (WCATSS) at The University of Oregon. Thanks to Piotr Pstragowski for explaining the material.

Definition: A groupoid is a category where all the morphisms are invertible. Alternatively, a groupoid is a set of objects A, a set of morphisms Γ, and a collection of maps as described by the diagram below.
To describe stacks, we compare them with sheaves. Both start out with a space X and a topology on it, so that we may consider open sets U.
In addition to these conditions, there is a triple intersection condition for stacks that does not have an analogous one in sheaves. It is given by:

for every Ui,Uj,Uk and si,sj,skˆF(Ui),ˆF(Uj),ˆF(Uk), respectively, such that there exist isomorphisms φij:si|UiUjsj|UiUj, φjk:sj|UjUksk|UjUk, and φik:si|UiUksk|UiUk, the diagram below commutes:
Example: A Hopf algebroid may be viewed as a functor into groupoids, so that with the appropriate topology, it becomes a stack. Indeed, by definition a Hopf algebroid is a pair of k-algebras (A,Γ) such that (Spec(A),Spec(Γ)) is a groupoid object in affine schemes, or in other words, is a functor from affine schemes into groupoids.

References: nLab (article on groupoids)

Morphisms of schemes

 Conference topic

This is from discussions at the 2016 West Coast Algebraic Topology Summer School (WCATSS) at The University of Oregon. Thanks to Zijian Yao for explaining the material.

Consider a morphism of schemes φ:SS and coherent sheaves F,G over S. Consider also a map of sheaves f:FG and a map f between the pullbacks of F and G, as described by the diagram below.
There are two natural questions to ask.
  1. When is f=φf?
  2. If we start with G over S, when is G=φG?
To answer these questions, consider fiber products of schemes and projections from them, as given below.
Remark: If 1. is true, then p1(f)=p2(f). If the previous statement is an equivalence, then φ is a morphism of descent.

Remark:
If 2. is true, then there exists α:p1(G)p2(G) such that π32(α)π21(α)=π31(α) and π(Δ)=α. If the previous statement is an equivalence, then φ is effective.

Thursday, August 11, 2016

What is a scheme?

 Conference topic

This is from a problem session at the 2016 West Coast Algebraic Topology Summer School (WCATSS) at The University of Oregon. Thanks to Tyler Lawson for explaining the material.

Definition: Affine schemes are the category Ringop. An object RRing becomes an object Spec(R) in affine schemes, and a ring map RS becomes a map Spec(S)Spec(R), where Spec denotes the set of prime ideals.

We try to think of Spec(R) as a geometrical object.

Example:
Let k be a field and consider the ring
R=k[x1,,xn]/(f1(x1,,xn),,fr(x1,,xn)).
Spec(R) is supposed to be a substitute for the set of solutions to a system of equations
f1(x1,,xn)=0,fr(x1,,xn)=0.

The scheme Spec(R) has a more precise definition. It consists of a set, a topology, and a sheaf. 

1. Set: The underlying set of the scheme Spec(R) is the set of prime ideals of R. For example:
  • if R=C[x], then the prime ideals are (xα) and (0);
  • if R=C[x,y], then the prime ideals are (xα,yβ), irreducible polynomials (f(x,y)), and (0).
2. Topology: For every ideal IR, the set V(I)={PR prime, PI} is a closed set. Note that
Nn=1V(In)=V(Nn=1In)andαIV(Iα)=V(αAIA).
Geometrically, the closed sets are sets of points where one or more identities (like f(x)=0) can hold. For example, if R=C[x], then we have three different closed set types: Spec(C[x]), , or a finite union of (xα1,,xαn). Solutions to equations can be one of the following types below.


3. Sheaf: Let X be a set with a topology. OX is the sheaf for which:
  • to each open set UX we get a ring OX(U);
  • to each containment VUX of open sets, there exists a restriction map resUV:OX(U)OX(V);
  • the restriction maps are compatible, in the sense that resVWresUV=resUW.
This is called the structure sheaf of X.

Say R is our ring, Spec(R) our set of primes, and we have some open set USpec(R). We like to think of it in the following way:
  • elements of R are functions;
  • elements of Spec(R) are points where we can evaluate a function fP (or where the function vanishes);
  • subsets SR are the sets {fR : f only vanishes at points outside U}.
Note that S is closed under multiplication. We localize R at S to get a set
S1R={[fs] : fR,sS},
for which OX(U)=S1R (good enough for today's purposes). Now we have a triple (Spec(R),τ,OX), for τ the Zariski topology, which we call a locally ringed space.

Definition: A scheme is a space X with a topology and a sheaf of rings that is locally isomorphic to Spec(R).

Since the sheaf has the space X and the topology (through the open sets) encoded in it, we may think of a scheme as a special type of sheaf. Also, isomorphism is meant in the category of locally ringed spaces.

Proposition: Morphisms of schemes Spec(R)Spec(S) are the same as ring maps SR.

Example: In the Zariski topology, take USpec(k[x,y]). Locally U looks like it is covered by rings, though that may not be the case globally. Indeed:

Example: Consider projective space P2, where [x:y:z]=[λx:λy:λz]. We may write
P2=U0U1U2.[1:y:z][x:1:z][x:y:1]Spec(k[y,z])Spec(k[x,z])Spec(k[x,y])
How can we express U0U1? This is left as an exercise.

Monday, August 8, 2016

Some facts about formal group laws

 Conference topic

Here we solve some problems from the 2016 West Coast Algebraic Topology Summer School (WCATSS) at The University of Oregon. Thanks to Piotr Pstragowski and Carolyn Yarnall for the solutions. First we recall some definitions.

Definition: Let R be a commutative ring with unit. A formal group law F over R is an element FR[[x,y]] satisfying
  1. F(x,y)=F(y,x) (symmetry), 
  2. F(x,0)=x and F(0,y)=y (uniticity),
  3. F(F(x,y),z)=F(x,F(y,z)) (associativity).
It follows from these three properties that F(x,y)=x+y+(higher order terms) for all F.

Proposition: For any formal group law F(x,y) over R, x has a formal inverse. That is, there exists an element i(x)R[[x]] such that F(x,i(x))=0.

Proof: Consider F(x,y+z), with |z|=n. Note that
\begin{align*} F(x,y+z) & = x+y +z +\sum_{i,j\geqslant 1} a_{ij} x^i(y+z)^j \\ & = x+y +z+\sum_{i,j\geqslant 1} a_{ij} x^i \sum_{k=0}^j \binom jk y^k z^{j-k} \\ & = x+y+z+\sum_{i,j\geqslant 1} a_{ij} x^i \left(y^j + \sum_{k=0}^{j-1} \binom jk y^k z^{j-k} \right)\\ & = x+y+z+\sum_{i,j\>1} a_{ij} x^i y^j  + \underbrace{\sum_{i,j\geqslant 1} a_{ij} x^i}_{\text{deg }\geqslant \ 1}\underbrace{\sum_{k=0}^{j-1} \binom jk y^k z^{j-k}}_{\text{deg }=\ k+n(j-k)\geqslant n}\\ & = F(x,y) + z + (\text{terms of deg }\geqslant\ n+1). \end{align*}
First choose z_1 to be the negative of all the degree-1 terms of F(x,0), so that F(x,z_1) has terms of degree 2 and higher. Now choose z_2 to be the negative of all the degree-2 terms of F(x,z_1), so F(x,z_1+z_2) has terms of degree 3 and higher. Continue in this manner ad infinitum to get a formal inverse \sum_i z_i (this will be a power series) of x. \square

Recall that we call f_a(x,y) = x+y the additive formal group law and F_m(x,y) = x+y+xy the multiplicative formal group law. Via the universal Lazard ring of formal group laws, these turn out to be the formal group laws of ordinary singular cohomology theory (additive) and complex K-theory KU (multiplicative). Recall also nested notation: for F a formal group law, we write
\begin{align*} [1]_F(x) & = x, \\ [2]_F(x) & = F(x,x), \\ [3]_F(x) & = F(F(x,x),x), \\ [4]_F(x) & = F(F(F(x,x),x),x), \end{align*}
and so on.

Definition: Let F be a formal group law over R. A morphism of formal group laws is an element \varphi\in R[[u]], giving a formal group law \varphi F\in R[[x,y]] by \varphi F(x,y):= F(\varphi(x),\varphi(y)).

An isomorphism of formal group laws is a morphism where the formal power series \varphi is an isomorphism.

Proposition: The additive formal group law and the multiplicative formal group law are not isomorphic over F_p.

Proof: We compare [p]_{F_m}(x) and [p]_{F_a}(x) and show they are not the same. If there were an isomorphism \varphi between F_a and F_m, we should have that
F_m(x,x) = F_a(\varphi(x),\varphi(x)) = \varphi(F_a(x,x)) \ \ \implies\ \ [p]_{F_m}(x) = \varphi([p]_{F_a}(x)),
since \varphi is a homomorphism. However, we first see that
[1]_{F_a}(x) = x ,\hspace{1cm} [2]_{F_a}(x) = F_a(x,x) = 2x ,\hspace{1cm} [3]_{F_a}(x) = F_a(F_a(x,x),x) = 3x,
and so continuing this pattern we get that [p]_{F_a}(x) = px = 0 in F_p. Next, for the multiplicative formal group law we find that
[1]_{F_m}(x) = x, ,\hspace{1cm} [2]_{F_m}(x) = F_m(x,x) = 2x + x^2 ,\hspace{1cm} [3]_{F_m}(x) = F_m(2x+x^2,x) = 3x + 3x^2 + x^3.
Here the pattern  is not immediate, but continuing these small examples we find that [p]_{F_m}(x) = (x+1)^p-1 = 1+x^p-1 = x^p in F_p. An isomorphism sends only 0 to 0, but in this case \varphi should send x^p\neq 0 to 0, a contradiction. Hence no such isomorphism exists over F_p. \square